9x^2-63x+27=0

Solution for 9x^2-63x+27=0 equation:

9x^2-63x+27=0

a = 9; b = -63; c = +27;
Δ = b2-4ac
Δ = -632-4·9·27
Δ = 2997
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2997}=\sqrt{81*37}=\sqrt{81}*\sqrt{37}=9\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-9\sqrt{37}}{2*9}=\frac{63-9\sqrt{37}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+9\sqrt{37}}{2*9}=\frac{63+9\sqrt{37}}{18}
$